Defect Report #023
Submission Date: 10 Dec 92
Source: X3J11/91-003 (Fred Tydeman)
Assuming that 99999 is larger than DBL_MAX_10_EXP, what
is the result of:
Is it 0.0, HUGE_VAL, or undefined?
Subclause 220.127.116.11 Floating constants on page 26, lines 30-32 says:
``The significand part is interpreted as a decimal rational number; the
digit sequence in the exponent part is interpreted as a decimal integer.
The exponent indicates the power of 10 by which the significand part is
to be scaled.'' In this case 0.0e99999 means 0.0 times
10 to the power 99999, or 0.0x1099999, which has a scaled value
of 0.0; therefore, return 0.0.
Subclause 18.104.22.168 The strtod function on page 151, lines
12-14 says: ``If the correct value is outside the range of representable
values, plus or minus HUGE_VAL is returned (according to
the sign of the value), and the value of the macro ERANGE
is stored in errno.'' Since the exponent (99999 in this
case) is larger than DBL_MAX_10_EXP, the value is outside
the range of representable values (overflow). Therefore, return HUGE_VAL.
Subclause 22.214.171.124.2 Characteristics of floating types <float.h>,
pages 14-16, describes the model that defines the floating-point types.
The number 0.0e99999, as written, is not part of that model
(it cannot be represented since the exponent is larger than emax).
From subclause 126.96.36.199 Floating types page 35, lines 11-13, ``...
if the value being converted is outside the range of values that can be
represented, the behavior is undefined.'' Therefore, since this number,
as written, has no representation, the behavior is undefined.
According to our response to Defect Report
#025, Question 1, the result of strtod("0.0e99999",
&ptr) is exactly representable, i.e., it lies within the range
of representable values. Therefore, by subclause 188.8.131.52, Returns,
the value zero shall be returned in this case, and errno
shall not be set. (This means that implementations have to test for the
special case of zero when creating floating-point representations from
Note also that strtod("0.0e-99999", &ptr)
is not a case of underflow, so errno shall not be set to
ERANGE in this case either.
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